Operating System MCQs

A. Segment base
B. Segment peak
C. Segment value
D. None of the mentioned

A. Starting logical address of the process
B. Starting physical address of the segment in memory
C. Segment length
D. None of the mentioned

A. Starting logical address of the process
B. Starting physical address of the segment in memory
C. Segment length
D. None of the mentioned

A. Greater than segment limit
B. Between 0 and segment limit
C. Between 0 and the segment number
D. Greater than the segment number

A. It is used as a physical memory address itself
B. It is subtracted from the segment base to produce the physical memory address
C. It is added to the segment base to produce the physical memory address
D. None of the mentioned

A. The segments are invalid
B. The processes get blocked
C. Segments are shared
D. All of the mentioned

A. Write only
B. Read only
C. Read €? write
D. None of the mentioned

A. 13 bits
B. 14 bits
C. 15 bits
D. 16 bits

A. 2048
B. 256
C. 64
D. 8

A. It reduces the memory access time to read or write a memory location
B. It helps to reduce the size of page table needed to implement the virtual address space of a process
C. It is required by the translation lookaside buffer
D. It helps to reduce the number of page faults in page replacement algorithms